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[前处理] abaqus程序中断

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 楼主| 发表于 2024-1-21 19:51:10 | 显示全部楼层 |阅读模式
本帖最后由 studying 于 2024-1-21 19:54 编辑

请问有大佬知道这种情况该咋办吗

The strain increment has exceeded fifty times the strain to cause first yield at 8236 points

The strain increment is so large that the program will not attempt the plasticity calculation at 6347 points

Solver problem. Numerical singularity when processing node SOIL-1.180 D.O.F. 2 ratio = 5.97900E+15.

Solver problem. Numerical singularity when processing node SOIL-1.175 D.O.F. 3 ratio = 144.979E+09  .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 1 ratio = 10.0483E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 2 ratio = 16.6190E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 3 ratio = 3.74090E+12.

The strain increment is so large that the program will not attempt the plasticity calculation at 6415 points

Solver problem. Numerical singularity when processing node SOIL-1.180 D.O.F. 2 ratio = 5.97900E+15.

Solver problem. Numerical singularity when processing node SOIL-1.175 D.O.F. 3 ratio = 144.979E+09  .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 1 ratio = 10.0483E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 2 ratio = 16.6190E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 3 ratio = 3.74090E+12.

The strain increment is so large that the program will not attempt the plasticity calculation at 6561 points

Solver problem. Numerical singularity when processing node SOIL-1.180 D.O.F. 2 ratio = 5.97900E+15.

Solver problem. Numerical singularity when processing node SOIL-1.175 D.O.F. 3 ratio = 144.979E+09  .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 1 ratio = 10.0483E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 2 ratio = 16.6190E+12 .

Solver problem. Numerical singularity when processing node SOIL-1.172 D.O.F. 3 ratio = 3.74090E+12.

The strain increment is so large that the program will not attempt the plasticity calculation at 6975 points

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